Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

public class Solution {

    public int compareVersion(String version1, String version2) {

        

        String tks1[] = version1.split("\\.");

        String tks2[] = version2.split("\\.");

        for(int i=0;i<tks1.length || i<tks2.length;i++) {

            int v1 = 0;

            int v2 = 0;

            if(i<tks1.length) v1 = Integer.parseInt(tks1[i]);

            if(i<tks2.length) v2 = Integer.parseInt(tks2[i]);

            if(v1<v2) return -1;

            else if(v1>v2) return 1;

        }

        return 0;

    }

}