For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3] ]
The minimum path sum from top to bottom is
11
(i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
public class Solution {
public int minimumTotal(ArrayList<ArrayList<Integer>> triangle) {
for(int i=triangle.size()-2;i>=0;i--) {
for(int j=0;j<triangle.get(i).size();j++) {
triangle.get(i).set(j, triangle.get(i).get(j) + (triangle.get(i+1).get(j)<triangle.get(i+1).get(j+1)?triangle.get(i+1).get(j):triangle.get(i+1).get(j+1)));
}
}
return triangle.get(0).get(0);
}
}
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