Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array
[1,2,3,4,5,6,7]
is rotated to [5,6,7,1,2,3,4]
.
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Related problem: Reverse Words in a String II
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public class Solution {
public void rotate(int[] nums, int k) {
k = k % nums.length;
int left = nums.length - k;
int right = k;
int[] leftNums = new int[left];
for (int i = 0; i < left; i++) {
leftNums[i] = nums[i];
}
int[] rightNums = new int[right];
for (int i = 0; i < right; i++) {
rightNums[i] = nums[i + left];
}
for (int i = 0; i < right; i++) {
nums[i] = rightNums[i];
}
for (int i = 0; i < left; i++) {
nums[i + right] = leftNums[i];
}
}
}
===========
public class Solution {
public void rotate(int[] nums, int k) {
k = k % nums.length;
reverse(nums, 0, nums.length - 1);
reverse(nums, 0, k - 1);
reverse(nums, k, nums.length - 1);
}
private void reverse(int[] nums, int s, int e) {
while (s < e) {
int tmp = nums[s];
nums[s] = nums[e];
nums[e] = tmp;
s++;
e--;
}
}
}
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